Класс DOMXPath

(PHP 5, PHP 7, PHP 8)

Введение

Поддерживает XPath 1.0

Обзор класса

class DOMXPath {

/* Свойства */

public readonly DOMDocument $document;

public bool $registerNodeNamespaces;

/* Методы */

public __construct(DOMDocument $document, bool $registerNodeNS = true)

public evaluate(string $expression, ?DOMNode $contextNode = null, bool $registerNodeNS = true): mixed

public query(string $expression, ?DOMNode $contextNode = null, bool $registerNodeNS = true): mixed

public static quote(string $str): string

public registerNamespace(string $prefix, string $namespace): bool

public registerPhpFunctions(string|array|null $restrict = null): void

}

Свойства

document
registerNodeNamespaces: Если установлено значение true, пространства имён регистрируются в узле.

Список изменений

Версия	Описание
8.4.0	Теперь невозможно клонировать объект DOMXPath. Это приведёт к выбрасыванию исключения. До версии PHP 8.4.0 это приводило к появлению непригодного для использования объекта.
8.0.0	Добавлено свойство `registerNodeNamespaces`.

Содержание

DOMXPath::__construct — Создаёт новый объект класса DOMXPath
DOMXPath::evaluate — Вычисляет переданное выражение XPath и возвращает типизированный результат, если возможно
DOMXPath::query — Оценивает XPath-выражение
DOMXPath::quote — Берёт в кавычки строку для XPath-выражения
DOMXPath::registerNamespace — Регистрирует пространство имён с объектом DOMXPath
DOMXPath::registerPhpFunctions — Регистрация PHP-функций как функций XPath

Улучшение страницы

Инструкция • Исправление • Сообщение об ошибке

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Примечания пользователей 5 notes

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Mark Omohundro, ajamyajax dot com ¶

15 years ago

<?php
// to retrieve selected html data, try these DomXPath examples:

$file = $DOCUMENT_ROOT. "test.html";
$doc = new DOMDocument();
$doc->loadHTMLFile($file);

$xpath = new DOMXpath($doc);

// example 1: for everything with an id
//$elements = $xpath->query("//*[@id]");

// example 2: for node data in a selected id
//$elements = $xpath->query("/html/body/div[@id='yourTagIdHere']");

// example 3: same as above with wildcard
$elements = $xpath->query("*/div[@id='yourTagIdHere']");

if (!is_null($elements)) {
  foreach ($elements as $element) {
    echo "<br/>[". $element->nodeName. "]";

    $nodes = $element->childNodes;
    foreach ($nodes as $node) {
      echo $node->nodeValue. "\n";
    }
  }
}
?>

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TechNyquist ¶

4 years ago

When working with XML (as a strict format) might be very important to give a namespace to XPath object in order to make it work properly.



I was experiencing "query" always returning empty node lists, it could not find anything. Only a broad "//*" was able to show off only the root element.



Then found out that registering the namespace reported in the "xmlns" attribute of the root element in the XPath object, and writing the namespace near the elements name, made it work properly.



So for an XML like this (from a sitemap):



<?xml version="1.0" encoding="UTF-8"?>

<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9">

    <url>

        <loc>http://example.com/index.php</loc>

        <lastmod>2005-01-01</lastmod>

        <changefreq>monthly</changefreq>

        <priority>0.5</priority>

    </url>

</urlset>



I needed the following XPath configuration:



<?php



    $doc = new DOMDocument;

    $doc->load("sitemap.xml");

    $xpath = new DOMXPath($doc);

    $xpath->registerNamespace('ns', 'http://www.sitemaps.org/schemas/sitemap/0.9');

    $nodes = $xpath->query('//ns:urlset/ns:url');



?>



Then again, that "xmlns" could be provided dynamically from the root element attribute of course.

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peter at softcoded dot com ¶

7 years ago

You may not always know at runtime whether your file has
a namespace or not. This can make it difficult to create
XPath queries. Use the seriously underdocumented
"namespaceURI" property of the documentElement of a
DOMDocument to determine if there is a namespace.
Use code such as the following:

$doc = new DOMDocument();
$doc->load($file);
$xpath = new DOMXPath($doc);
$ns = $doc->documentElement->namespaceURI;
if($ns) {
  $xpath->registerNamespace("ns", $ns);
  $nodes = $xpath->query("//ns:em[@class='glossterm']");
} else {
  $nodes = $xpath->query("//em[@class='glossterm']");
}
//look at nodes here

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peter at softcoded dot com ¶

7 years ago

Using XPath expressions can save a lot of programming
and allow you to home in on only the nodes you want.
Suppose you want to delete all empty <p> tags.
If you create a query using the following XPath expression,
you can find <p> tags that do not have any text
(other than spaces), any attributes,
any children or comments:

$expression = "//p[not(@*)  
   and not(*) 
   and not(./comment())
   and normalize-space(text())='']";
   
This expression will only find para tags that look like:

<p>[any number of spaces]</p>
<p></p>

Imagine the code you would have to add if you used
DOMDocument::getElementsByTagName("p") instead.

down

-5

archimedix32783262 at mailinator dot com ¶

10 years ago

Note that evaluate() will use the same encoding as the XML document.

So if you have a UTF-16 XML, you will have to query using UTF-16 strings.

You can use iconv() to convert from your code's encoding to the target encoding for better legibility.

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