PHP Conference Nagoya 2025

函数的参数和参数值

函数参数在函数签名中声明。通过参数值列表可以传递信息到函数,即以逗号作为分隔符的表达式列表。函数在实际调用之前,值参数是从左向右求值的(及早求值),并将结果赋值给函数的参数。

PHP 支持按值传递参数值(默认),通过引用传递参数以及默认参数。也支持可变长度参数列表命名参数

示例 #1 向函数传递数组

<?php
function takes_array($input)
{
echo
"$input[0] + $input[1] = ", $input[0]+$input[1];
}
?>

自 PHP 8.0.0 起,函数参数列表可以包含一个尾部的逗号,这个逗号将被忽略。这在参数列表较长或包含较长的变量名的情况下特别有用,这样可以方便地垂直列出参数。

示例 #2 函数参数使用尾部逗号

<?php
function takes_many_args(
$first_arg,
$second_arg,
$a_very_long_argument_name,
$arg_with_default = 5,
$again = 'a default string', // 在 8.0.0 之前,这个尾部的逗号是不允许的。
)
{
// ...
}
?>

通过引用传递参数值

默认情况下,函数参数值通过值传递(因而即使在函数内部改变参数值,它并不会改变函数外部的值)。如果希望允许函数修改它的参数值,必须通过引用传递。

如果想要函数的参数值始终通过引用传递,可以在函数定义中该参数的前面加上符号 &:

示例 #3 用引用传递函数参数值

<?php
function add_some_extra(&$string)
{
$string .= 'and something extra.';
}
$str = 'This is a string, ';
add_some_extra($str);
echo
$str; // 输出“This is a string, and something extra.”
?>

将常量表达式作为参数值传递给需要通过引用传递的参数是错误的。

默认参数的值

函数可以使用类似分配变量的语法定义参数的默认值。仅当参数未传递值时才使用默认值;注意传递 null 不会分配默认值。

示例 #4 在函数中使用默认参数

<?php
function makecoffee($type = "cappuccino")
{
return
"Making a cup of $type.\n";
}
echo
makecoffee();
echo
makecoffee(null);
echo
makecoffee("espresso");
?>

以上示例会输出:

Making a cup of cappuccino.
Making a cup of .
Making a cup of espresso.

默认参数值可以是标量值、array、特殊类型 null,以及从 PHP 8.1.0 开始,使用 new ClassName() 语法的对象。

示例 #5 使用非标量类型作为默认参数

<?php
function makecoffee($types = array("cappuccino"), $coffeeMaker = NULL)
{
$device = is_null($coffeeMaker) ? "hands" : $coffeeMaker;
return
"Making a cup of ".join(", ", $types)." with $device.\n";
}
echo
makecoffee();
echo
makecoffee(array("cappuccino", "lavazza"), "teapot");?>

以上示例会输出:

Making a cup of cappuccino with hands.
Making a cup of cappuccino, lavazza with teapot.

示例 #6 使用对象作为默认值(自 PHP 8.1.0 起)

<?php
class DefaultCoffeeMaker {
public function
brew() {
return
"Making coffee.\n";
}
}
class
FancyCoffeeMaker {
public function
brew() {
return
"Crafting a beautiful coffee just for you.\n";
}
}
function
makecoffee($coffeeMaker = new DefaultCoffeeMaker)
{
return
$coffeeMaker->brew();
}
echo
makecoffee();
echo
makecoffee(new FancyCoffeeMaker);
?>

以上示例会输出:

Making coffee.
Crafting a beautiful coffee just for you.

默认值必须是常量表达式,不能是诸如变量,类成员,或者函数调用等。

注意任何可选参数都应在强制参数之后指定,否则可选参数不能在调用时省略。考虑以下示例:

示例 #7 函数默认参数的不正确用法

<?php
function makeyogurt($container = "bowl", $flavour)
{
return
"Making a $container of $flavour yogurt.\n";
}

echo
makeyogurt("raspberry"); // "raspberry" 是 $container, 不是 $flavour
?>

以上示例会输出:

Fatal error: Uncaught ArgumentCountError: Too few arguments
 to function makeyogurt(), 1 passed in example.php on line 42

现在,比较上面的例子和这个例子:

示例 #8 函数默认参数正确的用法

<?php
function makeyogurt($flavour, $container = "bowl")
{
return
"Making a $container of $flavour yogurt.\n";
}

echo
makeyogurt("raspberry"); // "raspberry" 是 $flavour
?>

以上示例会输出:

Making a bowl of raspberry yogurt.

自 PHP 8.0.0 起,命名参数可用于跳过多个可选参数。

示例 #9 函数默认参数正确的用法

<?php
function makeyogurt($container = "bowl", $flavour = "raspberry", $style = "Greek")
{
return
"Making a $container of $flavour $style yogurt.\n";
}

echo
makeyogurt(style: "natural");
?>

以上示例会输出:

Making a bowl of raspberry natural yogurt.

自 PHP 8.0.0 起,弃用在可选参数之后声明强制参数。这通常可以通过删除默认值来解决,因为它永远不会被使用。唯一的例外是 Type $param = null 类型的参数,其中默认 null 使得该类型可以隐式为 null。自 PHP 8.4.0 起,此用法已弃用,而应改用显式可为 null 类型

示例 #10 强制参数后声明可选参数

<?php

function foo($a = [], $b) {} // 默认不使用;自 PHP 8.0.0 起弃用
function foo($a, $b) {} // 功能相同,无弃用通知

function bar(A $a = null, $b) {} // 自 PHP 8.1.0 起,$a 是隐式必需的
// (因为其位于必需的参数之前),
// 但隐式可为 null(自 PHP 8.4.0 起已弃用),
// 因为默认参数值为 null
function bar(?A $a, $b) {} // 推荐

?>

注意: 自 PHP 7.1.0 起,省略未指定默认值的参数会原因引发 ArgumentCountError;在此之前的版本会引发警告。

注意: 期望通过引用传参的参数可以有默认值。

可变数量的参数值列表

PHP 在用户自定义函数中支持可变数量的参数值列表。由 ... 语法实现。

参数列表可能包含 ... 记号,表示该函数接受可变数量的参数值。参数值将作为 array 传递到指定变量中:

示例 #11 使用 ... 来访问变量参数值

<?php
function sum(...$numbers) {
$acc = 0;
foreach (
$numbers as $n) {
$acc += $n;
}
return
$acc;
}

echo
sum(1, 2, 3, 4);
?>

以上示例会输出:

10

... 也可以在调用函数时将 arrayTraversable 变量或文字解包到参数值列表中使用:

示例 #12 使用 ... 来传递参数

<?php
function add($a, $b) {
return
$a + $b;
}

echo
add(...[1, 2])."\n";

$a = [1, 2];
echo
add(...$a);
?>

以上示例会输出:

3
3

可以在 ... 前指定正常的位置参数。在这种情况下,只有不符合位置参数的尾部参数才会被添加到 ... 生成的数组中。

也可以在 ... 标记前添加 类型声明。如果存在这种情况,那么 ... 捕获的所有参数都必须匹配参数类型。

示例 #13 输入提示的变量参数

<?php
function total_intervals($unit, DateInterval ...$intervals) {
$time = 0;
foreach (
$intervals as $interval) {
$time += $interval->$unit;
}
return
$time;
}

$a = new DateInterval('P1D');
$b = new DateInterval('P2D');
echo
total_intervals('d', $a, $b).' days';

// 这将会失败,因为 null 不是 DateInterval 对象。
echo total_intervals('d', null);
?>

以上示例会输出:

3 days
Catchable fatal error: Argument 2 passed to total_intervals() must be an instance of DateInterval, null given, called in - on line 14 and defined in - on line 2

最后,可变参数值也可以通过在 ... 前面加上 & 来通过引用传递。

命名参数

PHP 8.0.0 开始引入了命名参数作为现有位置参数的扩展。命名参数允许根据参数名而不是参数位置向函数传参。这使得参数的含义自成体系,参数与顺序无关,并允许任意跳过默认值。

命名参数通过在参数名前加上冒号来传递。允许使用保留关键字作为参数名。参数名必须是一个标识符,不允许动态指定。

示例 #14 命名参数的语法

<?php
myFunction
(paramName: $value);
array_foobar(array: $value);

// 不支持。
function_name($variableStoringParamName: $value);
?>

示例 #15 通过位置传参与命名参数的对比

<?php
// 使用顺序传递参数:
array_fill(0, 100, 50);

// 使用命名参数:
array_fill(start_index: 0, count: 100, value: 50);
?>

指定参数的传递顺序并不重要。

示例 #16 参数顺序不同的示例(同上例)

<?php
array_fill
(value: 50, count: 100, start_index: 0);
?>

命名参数也可以与位置参数相结合使用。此种情况下,命名参数必须在位置参数之后。也可以只指定一个函数的部分可选参数,而不考虑它们的顺序。

示例 #17 命名参数与位置参数结合使用

<?php
htmlspecialchars
($string, double_encode: false);
// 等价于
htmlspecialchars($string, ENT_QUOTES | ENT_SUBSTITUTE | ENT_HTML401, 'UTF-8', false);
?>

传递多个参数值给同一个命名参数会导致 Error 异常。

示例 #18 传递多个参数值到相同命名参数将会导致抛出 Error

<?php

function foo($param) { ... }

foo(param: 1, param: 2);
// 错误:命名参数 $param 覆盖了之前的参数

foo(1, param: 2);
// 错误:命名参数 $param 覆盖了之前的参数

?>

自 PHP 8.1.0 起,可以在解包参数后面使用命名参数。命名参数不能覆盖已解包的参数。

示例 #19 解包后使用命名参数

<?php
function foo($a, $b, $c = 3, $d = 4) {
return
$a + $b + $c + $d;
}

var_dump(foo(...[1, 2], d: 40)); // 46
var_dump(foo(...['b' => 2, 'a' => 1], d: 40)); // 46

var_dump(foo(...[1, 2], b: 20)); // Fatal error。命名参数 $b 覆盖之前的参数
?>
添加备注

用户贡献的备注 8 notes

up
131
php at richardneill dot org
9 years ago
To experiment on performance of pass-by-reference and pass-by-value, I used this script. Conclusions are below.

#!/usr/bin/php
<?php
function sum($array,$max){ //For Reference, use: "&$array"
$sum=0;
for (
$i=0; $i<2; $i++){
#$array[$i]++; //Uncomment this line to modify the array within the function.
$sum += $array[$i];
}
return (
$sum);
}

$max = 1E7 //10 M data points.
$data = range(0,$max,1);

$start = microtime(true);
for (
$x = 0 ; $x < 100; $x++){
$sum = sum($data, $max);
}
$end = microtime(true);
echo
"Time: ".($end - $start)." s\n";

/* Run times:
# PASS BY MODIFIED? Time
- ------- --------- ----
1 value no 56 us
2 reference no 58 us

3 valuue yes 129 s
4 reference yes 66 us

Conclusions:

1. PHP is already smart about zero-copy / copy-on-write. A function call does NOT copy the data unless it needs to; the data is
only copied on write. That's why #1 and #2 take similar times, whereas #3 takes 2 million times longer than #4.
[You never need to use &$array to ask the compiler to do a zero-copy optimisation; it can work that out for itself.]

2. You do use &$array to tell the compiler "it is OK for the function to over-write my argument in place, I don't need the original
any more." This can make a huge difference to performance when we have large amounts of memory to copy.
(This is the only way it is done in C, arrays are always passed as pointers)

3. The other use of & is as a way to specify where data should be *returned*. (e.g. as used by exec() ).
(This is a C-like way of passing pointers for outputs, whereas PHP functions normally return complex types, or multiple answers
in an array)

4. It's unhelpful that only the function definition has &. The caller should have it, at least as syntactic sugar. Otherwise
it leads to unreadable code: because the person reading the function call doesn't expect it to pass by reference. At the moment,
it's necessary to write a by-reference function call with a comment, thus:
$sum = sum($data,$max); //warning, $data passed by reference, and may be modified.

5. Sometimes, pass by reference could be at the choice of the caller, NOT the function definitition. PHP doesn't allow it, but it
would be meaningful for the caller to decide to pass data in as a reference. i.e. "I'm done with the variable, it's OK to stomp
on it in memory".
*/
?>
up
13
Simmo at 9000 dot 000
2 years ago
For anyone just getting started with php or searching, for an understanding, on what this page describes as a "... token" in Variable-length arguments:
https://www.php.net/manual/en/functions.arguments.php#functions.variable-arg-list
<?php

func
($a, ...$b)

?>
The 3 dots, or elipsis, or "...", or dot dot dot is sometimes called the "spread operator" in other languages.

As this is only used in function arguments, it is probably not technically an true operator in PHP. (As of 8.1 at least?).

(With having an difficult to search for name like "... token", I hope this note helps someone).
up
18
LilyWhite
3 years ago
It is worth noting that you can use functions as function arguments

<?php
function run($op, $a, $b) {
return
$op($a, $b);
}

$add = function($a, $b) {
return
$a + $b;
};

$mul = function($a, $b) {
return
$a * $b;
};

echo
run($add, 1, 2), "\n";
echo
run($mul, 1, 2);
?>

Output:
3
2
up
16
Hayley Watson
7 years ago
There are fewer restrictions on using ... to supply multiple arguments to a function call than there are on using it to declare a variadic parameter in the function declaration. In particular, it can be used more than once to unpack arguments, provided that all such uses come after any positional arguments.

<?php

$array1
= [[1],[2],[3]];
$array2 = [4];
$array3 = [[5],[6],[7]];

$result = array_merge(...$array1); // Legal, of course: $result == [1,2,3];
$result = array_merge($array2, ...$array1); // $result == [4,1,2,3]
$result = array_merge(...$array1, $array2); // Fatal error: Cannot use positional argument after argument unpacking.
$result = array_merge(...$array1, ...$array3); // Legal! $result == [1,2,3,5,6,7]
?>

The Right Thing for the error case above would be for $result==[1,2,3,4], but this isn't yet (v7.1.8) supported.
up
28
gabriel at figdice dot org
8 years ago
A function's argument that is an object, will have its properties modified by the function although you don't need to pass it by reference.

<?php
$x
= new stdClass();
$x->prop = 1;

function
f ( $o ) // Notice the absence of &
{
$o->prop ++;
}

f($x);

echo
$x->prop; // shows: 2
?>

This is different for arrays:

<?php
$y
= [ 'prop' => 1 ];

function
g( $a )
{
$a['prop'] ++;
echo
$a['prop']; // shows: 2
}

g($y);

echo
$y['prop']; // shows: 1
?>
up
12
boan dot web at outlook dot com
6 years ago
Quote:

"The declaration can be made to accept NULL values if the default value of the parameter is set to NULL."

But you can do this (PHP 7.1+):

<?php
function foo(?string $bar) {
//...
}

foo(); // Fatal error
foo(null); // Okay
foo('Hello world'); // Okay
?>
up
4
Luna
1 year ago
When using named arguments and adding default values only to some of the arguments, the arguments with default values must be specified at the end or otherwise PHP throws an error:

<?php

function test1($a, $c, $b = 2)
{
return
$a + $b + $c;
}

function
test2($a, $b = 2, $c)
{
return
$a + $b + $c;
}

echo
test1(a: 1, c: 3)."\n"; // Works
echo test2(a: 1, c: 3)."\n"; // ArgumentCountError: Argument #2 ($b) not passed

?>

I assume that this happens because internally PHP rewrites the calls to something like test1(1, 3) and test2(1, , 3). The first call is valid, but the second obviously isn't.
up
5
Hayley Watson
7 years ago
If you use ... in a function's parameter list, you can use it only once for obvious reasons. Less obvious is that it has to be on the LAST parameter; as the manual puts it: "You may specify normal positional arguments BEFORE the ... token. (emphasis mine).

<?php
function variadic($first, ...$most, $last)
{
/*etc.*/}

variadic(1, 2, 3, 4, 5);
?>
results in a fatal error, even though it looks like the Thing To Do™ would be to set $first to 1, $most to [2, 3, 4], and $last to 5.
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