ArrayIterator::next

(PHP 5, PHP 7, PHP 8)

ArrayIterator::next — 次のエントリに移動する

説明

public ArrayIterator::next(): void

この関数は次のエントリにイテレータを移動します。

パラメータ

この関数にはパラメータはありません。

戻り値

値を返しません。

例

例1 ArrayIterator::next() の例

<?php
$arrayobject = new ArrayObject();

$arrayobject[] = 'zero';
$arrayobject[] = 'one';

$iterator = $arrayobject->getIterator();

while($iterator->valid()) {
    echo $iterator->key() . ' => ' . $iterator->current() . "\n";

    $iterator->next();
}
?>

上の例の出力は以下となります。

0 => zero
1 => one

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User Contributed Notes 1 note

down

onelsonsenna at gmail dot com ¶

13 years ago

If you use exchangeArray method of ArrayObject and then next method of ArrayIterator like this:

<?php
    
    $fruits = array("apple", "grape", "lemon");

    $colors = array("blue", "yellow", "green");

    $arrayObject = new ArrayObject($fruits);
    
    $arrayIterator = $arrayObject->getIterator();

    while($arrayIterator->valid()) {

        if ($arrayIterator->current() == "grape") {
            $arrayObject->exchangeArray($colors);
        }

        $arrayIterator->next();
    }

?>

You will receive:

PHP Notice:  ArrayIterator::next(): Array was modified outside object and internal position is no longer valid

So be careful with next and prev operations. :)

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