ArrayIterator::getArrayCopy

    (PHP 5, PHP 7, PHP 8)

    ArrayIterator::getArrayCopy — 配列のコピーを取得する

    説明

    public ArrayIterator::getArrayCopy(): array

    配列のコピーを取得します。

    警告

    この関数は、 現在のところ詳細な情報はありません。引数のリストのみが 記述されています。

    パラメータ

    この関数にはパラメータはありません。

    戻り値

    配列のコピーを返します。 ArrayIterator がオブジェクトを参照している場合は public プロパティの配列を返します。

    参考

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    User Contributed Notes 2 notes

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    3
    irvine L
    6 years ago
    Just in case some of you out there do NOT know this:

    (a). 'getArrayCopy()', returns a copy of the ORIGINAL array - iterator object. Therefore, using (for example) 'LimitIterator' on an array-object, and then calling 'getArrayCopy' afterwards, might not return the current (adjusted) object.

    (b). Instead, use the 'iterator_to_array' function, in order to access, or return, the current state of the array-object-iterator (whatever). Using the example above (in '(a)'); passing the 'LimitIterator' object into 'iterator_to_array', should return the CURRENT, and NOT ORIGINAL state of your array (iterator object).
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    2
    lenye01 at gmail dot com
    13 years ago
    the difference of this method and the direct assign the object to a value is as follows:

    <?php
    $b     = array('name'=>'mengzhi','age'=>'12','city'=>'shanghai');
    $a = new ArrayIterator($b);
    $a->append(array('home'=>'china','work'=>'developer'));
    $c = $a->getArrayCopy();
    var_dump($a);
    var_dump($c);
    ?>
    result:
    object(ArrayIterator)#1 (1) { ["storage":"ArrayIterator":private]=> array(4) { ["name"]=> string(7) "mengzhi" ["age"]=> string(2) "12" ["city"]=> string(8) "shanghai" [0]=> array(2) { ["home"]=> string(5) "china" ["work"]=> string(9) "developer" } } }

    array(4) { ["name"]=> string(7) "mengzhi" ["age"]=> string(2) "12" ["city"]=> string(8) "shanghai" [0]=> array(2) { ["home"]=> string(5) "china" ["work"]=> string(9) "developer" } }
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