filter_has_var

(PHP 5 >= 5.2.0, PHP 7, PHP 8)

filter_has_var — 检测是否存在指定类型的变量

说明

filter_has_var(int $input_type, string $var_name): bool

参数

input_type: INPUT_GET、INPUT_POST、INPUT_COOKIE、INPUT_SERVER、INPUT_ENV 里的其中一个。
var_name: 要检查的变量名。

返回值

成功时返回 true，或者在失败时返回 false。

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用户贡献的备注 2 notes

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drm at melp dot nl ¶

15 years ago

Please note that the function does not check the live array, it actually checks the content received by php:

<?php
$_GET['test'] = 1;
echo filter_has_var(INPUT_GET, 'test') ? 'Yes' : 'No';
?>

would say "No", unless the parameter was actually in the querystring.

Also, if the input var is empty, it will say Yes.

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nanhe dot kumar at gmail dot com ¶

11 years ago

Through this example i think you can better understand

    if ( !filter_has_var(INPUT_GET, 'email') ) {
        echo "Email Not Found";
    }else{
        echo "Email Found";
    }
    Output

    localhost/nanhe/test.php?email=1 //Email Found
    localhost/nanhe/test.php?email //Email Found
    http://localhost/nanhe/test.php //Email Not Found

Consider on second example

http://localhost/nanhe/test.php
$_GET['email']="info@nanhe.in";
if ( !filter_has_var(INPUT_GET, 'email') ) {
        echo "Email Not Found";
    }else{
        echo "Email Found";
    }
But output will be Email Not Found