ReflectionClass::hasMethod

(PHP 5 >= 5.1.2, PHP 7, PHP 8)

ReflectionClass::hasMethodПроверяет, задан ли метод

Описание

public ReflectionClass::hasMethod(string $name): bool

Проверяет, определён ли в классе указанный метод или нет.

Список параметров

name

Имя проверяемого метода.

Возвращаемые значения

true, если метод определён, в противном случае false

Примеры

Пример #1 Пример использования ReflectionClass::hasMethod()

<?php
Class C {
public function
publicFoo() {
return
true;
}

protected function
protectedFoo() {
return
true;
}

private function
privateFoo() {
return
true;
}

static function
staticFoo() {
return
true;
}
}

$rc = new ReflectionClass("C");

var_dump($rc->hasMethod('publicFoo'));

var_dump($rc->hasMethod('protectedFoo'));

var_dump($rc->hasMethod('privateFoo'));

var_dump($rc->hasMethod('staticFoo'));

// C не имеет метода bar
var_dump($rc->hasMethod('bar'));

// Имена методов регистронезависимые
var_dump($rc->hasMethod('PUBLICfOO'));
?>

Результат выполнения приведённого примера:

bool(true)
bool(true)
bool(true)
bool(true)
bool(false)
bool(true)

Смотрите также

Добавить

Примечания пользователей 6 notes

up
4
phoenix at todofixthis dot com
14 years ago
Parent methods (regardless of visibility) are also available to a ReflectionObject. E.g.,

<?php
class ParentObject {
public function
parentPublic( ) {
}

private function
parentPrivate( ) {
}
}

class
ChildObject extends ParentObject {
}

$Instance = new ChildObject();
$Reflector = new ReflectionObject($Instance);

var_dump($Reflector->hasMethod('parentPublic')); // true
var_dump($Reflector->hasMethod('parentPrivate')); // true
?>
up
1
dn dot permyakov at gmail dot com
5 years ago
Trait methods can be seen by both actual and alias names

<?php

trait Sauce
{
public function
getSpicy()
{
return
'Cayenne';
}
}

class
Sandwich
{
use
Sauce {
Sauce::getSpicy as getSweet;
}
}

$class = new \ReflectionClass('Sandwich');
var_dump($class->hasMethod('getSweet'));
var_dump($class->hasMethod('getSpicy'));
?>
bool(true)
bool(true)
up
0
flancer64 at gmail dot com
8 years ago
Annotated methods that are implemented using PHP magic methods are not recognized by "hasMethod".

<?php
/**
* @method void annotatedMethod()
*/
class SomeClass
{
public function
__call($name, $arguments)
{
echo
"this is magic method: $name.\n";
}

public function
codedMethod()
{
echo
"this is coded method.\n";
}
}

$obj = new \SomeClass();
$obj->codedMethod();
$obj->annotatedMethod();

$ref = new ReflectionClass(\SomeClass::class);
echo
"SomeClass has 'codedMethod': " . json_encode($ref->hasMethod('codedMethod')) . ".\n";
echo
"SomeClass has 'annotatedMethod': " . json_encode($ref->hasMethod('annotatedMethod')) . ".\n";
?>

Output:

this is coded method.
this is magic method: annotatedMethod.
SomeClass has 'codedMethod': true.
SomeClass has 'annotatedMethod': false.
up
0
hanguofeng at gmail dot com
14 years ago
note that even if private method will also be 'has'.
up
-1
Xorifelse
7 years ago
It might be interesting to know that this is the only method to determine if a trait has a specific method:

trait a{
function __wakeup(){}
}

class b{}

class c{
use a;
}

var_dump((new ReflectionClass('a'))->hasMethod('__wakeup')); // true
var_dump((new ReflectionClass('b'))->hasMethod('__wakeup')); // false
var_dump((new ReflectionClass('c'))->hasMethod('__wakeup')); // true
up
-4
michaelgranados at gmail dot com
12 years ago
A way to check if you can call an method over a class:

<?php
function is_public_method(
/* string */$className,
/* string */$method
){
$classInstance = new ReflectionClass($className);
if (
$classInstance->hasMethod($method)) {
return
false;
}
$methodInstance = $instance->getMethod($method);
return
$methodInstance->isPublic();
}
?>
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